3x^2-15x=-3x^2-2x-7

Solution for 3x^2-15x=-3x^2-2x-7 equation:

3x^2-15x=-3x^2-2x-7

We move all terms to the left:

3x^2-15x-(-3x^2-2x-7)=0

We get rid of parentheses

3x^2+3x^2+2x-15x+7=0

We add all the numbers together, and all the variables

6x^2-13x+7=0

a = 6; b = -13; c = +7;
Δ = b2-4ac
Δ = -132-4·6·7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-1}{2*6}=\frac{12}{12}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+1}{2*6}=\frac{14}{12}
=1+1/6
$